The average force necessary to stop a hammer with momentum p Ns in 0.5 s is
(1) 2PN
(2) PN
(3) 4p N
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Answered by
18
Answer:
2PN
Explanation:
initial momentum =p
final momentum =0
change in momentum =p
therefore average force required =p/0.5
=2pN
hence answer is 2pN
Answered by
9
Answer:
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