Math, asked by harshshah996642, 18 days ago

The average income (in Rs.) earned by hawkers in a city are given below. Prepare an exclusive frequency distribution for the data. It is given that mid value of one class is 450 and class-length is 100.
313, 236, 253, 470, 753, 772, 491, 387, 339, 276 269, 247, 360 ,460, 281 ,402, 242, 278 ,303 ,480, 622, 313, 276, 304 ,537, 487, 358, 350 880 700, 260, 293 ,844 ,360, 363 ,243, 799 ,691, 833, 507​
plz help me

Answers

Answered by harshchhawal233
0

Answer:

Class-Intervals

mid-values

x

i

f

i

d

i

=x

i

−47.5 u

i

=

3

x

i

=47.5

f

i

u

i

40−43 41.5 31 −6 −2 −62

43−46 44.5 58 −3 −1 −58

46−52 47.5 60 0 0 0

49−52 50.5 f 3 1 f

52−55 53.5 27 6 2 54

N=∑f

i

=176+f ∑f

i

u

i

=f−66

We have,

X

= 42.7 , A= 47. 5 and h=3

X

=A+h[

N

1

∑f

i

u

i

]

⇒47.2=47.5+3×[

176+f

f−66

]

⇒−0.3=3×[

176+f

f−66

]

10

−1

=

176+f

f−66

⇒−176−f=10f−660

⇒11f=484⇒f=44

Hence, the missing frequency is 44.

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