Question

The average K.E. of an ideal gas in calories per mole is approximately equal to *

1 point

A) Three times the absolute temperature

B) absolute temperature

C) two times the absolute

D) 1.5 times the absolute temperature




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Answer 1

Answer:

A

Explanation:

K.E =3/2.RT=3/2.2T sinceR~=2calK-

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