Question

The average kinetic energy of 28 g CO at, 300 K is E kcal. The average kinetic energy of 2 g H₂ at the same temperature would be..... k cal.
(a) E
(b) 14 E
(c) 1/14 E
(c) 28 E

Answer 1

$<b>$
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$\mathbb{NICE...QUESTION}$

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→ [B]


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Answer 2

Given - Mass of CO and H2: 28 grams and 2 gram respectively

Kinetic energy of CO = E

Find - Kinetic energy of H2

Solution - The kinetic energy can be calculated using the formula KE = 1/2*m*v², where m is mass and v is velocity.

Firstly we will be finding out the velocity of molecules from the using the kinetic energy information of CO.

E = 1/2*28*v²

v² = E/14

Now, using the same velocity to find Kinetic energy of H2.

Kinetic energy = 1/2*2*E/14

Kinetic energy = E/14

Hence, the average kinetic energy of 2 g H₂ at the same temperature would be E/14 k cal.