Question

The average kinetic energy of a gas molecule at
27°C is 6.2 * 10-21 J. Its average kinetic energy at
227°C will be
[NCERT Pg. 330]
(1) 58.6 x 10-21 j
(2) 8.32 * 10-21
(3) 10.33 x 10-21 J
(4) 13.72 * 10-21 J​

Answer 1

Answer:

(3) 10.33 * 10-21

Explanation:

Correct option is

C 10.35×10 −21 Joule

Mean KE= 23kT

so 6.21×10 −21

=3k×300/2

so k=1.38×10 −23

KE at 500 K ,

KE=3×1.38×10 −23×500/2

=10.35×10 −21 Joule