Question

The average kinetic energy of an ideal gas , per molecule in SI units at 25°C will be?

Answer 1

K.E= 3/2 kt , k is constant put the value get the answer.. Temperature must be in Kelvin..

Answer 2

Answer : The average kinetic energy of an ideal gas per molecule will be, $616.86\times 10^{-23}J$

Solution :

The formula of the average kinetic energy per molecule will be,

$\nu_{av}=\frac{3}{2}KT$

where,

$\nu_{av}$ = average kinetic energy

K = Boltzmann constant = $1.38\times 10^{-23}J/K$

T = temperature of gas = $25^oC=273+25=298K$

Now put all the given values in the above formula, we get the average kinetic energy per molecule.

$\nu_{av}=\frac{3}{2}\times (1.38\times 10^{-23}J/K)\times (298K)=616.86\times 10^{-23}J$

Therefore, the average kinetic energy of an ideal gas per molecule will be, $616.86\times 10^{-23}J$