The average kinetic energy of an ideal gas, per
molecule in S.l. units, at 25°C will be
(1) 6.17 * 10-20 J (2) 7.16 * 10-20
(3) 61.7 * 10-21 J 14 6.17 * 10-21
Answers
Answered by
7
Answer:
(d) 6.17 x 10-21 J
Explanation:
Temperature=25℃=298K
Therefore K.E per molecule =3RT/2NA =3×8.314×298\2×6.02×10^23 = 6.17 ×10^-21 J
Similar questions