Question

The average kinetic energy of He gas at a temperature TdegreeC is K. The
temperature at which H2(g) will have same value of average kinetic energy is
(assume the same mol of He and H2).
*T/2 degree C
*2T degree C
*T-273/2 degree C
*T degree C​

Answer 1

Answer:

Calculate (a) the average kinetic energy of translation of an oxygen molecule at 27∘C (b) the total kinetic energy of an oxygen molecule at 27∘C (c ) the total kinetic energy in joule of one mole of oxygen at 27∘. Given Avogadro's number =6.02×1023 and Boltzmann's constant =1.38×10-23J/(mol-K).

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