Question

The average kinetic energy of molecules in a gas at temperature T is 1.5 kT. Find the temperature at which the average kinetic energy of the molecules of hydrogen equals the binding energy of its atoms. Will hydrogen remain in molecular from at this temperature? Take k = 8.62 × 10−5 eV K−1.

Answer 1

The temperature at which the average kinetic energy of the molecules of hydrogen equals the binding energy of its atom is $1.05 \times 10^{-5} K$

Explanation:

At temperature T, the molecules average kinetic energy K in a gas is shown as K = 32kT.

where,

$k = 8.62 \times 10^{-5} eV K^{-1}$

T = Gas’ temperature  

Hydrogen atom has the binding energy = 13.6 eV.

As per the information provided in the question,

Hydrogen atom’s binding energy = Hydrogen molecules has the average kinetic energy

Therefore, 1.5 kT = 13.6

⇒$T = 8.62 \times 13.61.5 \times 10^{-5} = 1.05 \times10^{-5} K$

For hydrogen, at such a high temperature, there is no possibility for remaining in the molecular state.

Answer 2

Answer:

Above answer is... correct........m