Question

the average kinetic energy per molecule of an ideal gas at 27°C is (where NA is avogadro's number)​

Answer 1

Answer:

Given :

T = 27 + 273 = 300K

Average kinetic energy per molecule :

=

2

3

kT=

2

3

N

0

R

T

=

2

3

×

6.023×10

23

8.314

×300

=6.21×10

−21

JK

−1

molecule

−1

.