Question

The average kinetics energy of a spring block system execting SHM on a smooth horizontal surface is (K = spring constant, A = amplitude)

Answer 1

Given that,

Spring constant = K

Amplitude = A

Amplitude :

Amplitude is equal to the maximum position of the block.

$A = x\ cm$

We know that,

Kinetic energy :

Kinetic energy of a spring block is equal to the half of the spring constant multiply by square of amplitude.

In mathematically form,

$K.E=\dfrac{1}{2}kA^2$

We need to calculate the average kinetics energy of a spring block system

Using formula of kinetic energy

$K.E=\dfrac{1}{2}kx^2$

Where, k = spring constant

x = maximum position

Put the value into the formula

$K.E=\dfrac{1}{2}kA^2$

Hence, The average kinetics energy of a spring block system is $\dfrac{1}{2}kA^2$