Computer Science, asked by vijay7426, 1 year ago

the average mark obtained by 22 candidates in an examination is 45.the average of the first ten is 50 while the last eleven is 40.the marks obtained by the 11th candidate is ?​

Answers

Answered by chiselaqe
2

The mark of the 11th Candidate must be 50 because you need to find the total mark which is 22*45 and deduct (10*50)+(11*40). =990-(500+440)

                                                                                 =990-940

                                                                                 =50 marks

Answered by ROYALSTUDYEDU
3

Answer:

A

Explanation:

Total marks scored by 22 candidates =22×45=990

Total marks scored by first 10 candidates =10×55=550

Total marks scored by last 11 candidates =11×40=440

∴ Marks scored by 11th candidatte =990−(550+440)=0

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