Math, asked by Anonymous, 8 months ago

The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102, 152. What is the average of the extracted scores that are extreme values (outliers)?

Answers

Answered by sonuvuce
0

The average of the extracted scores that are extreme values is 102

Step-by-step explanation:

Given average mark of candidate (Mean) = 128.5

Standard Deviation = 8.2

As per mean and standard deviation method, the extreme values (outliers) are beyond the range

Mean ± 3 × Standard Deviation

This range will be

128.5 - 3 × 8.2 to 128.5 + 3 × 8.2

= 103.9 to 153.1

The three scores extracted are 148, 102, 152

Out of these three scores only 102 is beyond the range above

Therefore, only 102 is the outlier

The average will be 102 only.

Hope this answer is helpful.

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Answered by amitnrw
0

Given : The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

To find : average of the extracted scores that are the extreme values (outliers)

Solution:

The average marks of candidates in an aptitude test was 128.5

=> Mean = 128.5

Standard Deviation = 8.2

outlier will be out sides   then range    Mean  ± 3* SD

128.5 ± 8.2 × 3

= 128.5 ± 24.6

Range is   ( 103.9  ,  153.1)

102 is outside this range

Hence outlier would be 102

Average of 102   will be 102

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