Question

The average mark of candidates in an aptitude test was 128.5 with a standard deviation of
8.2. Three scores extracted from the test are; 148, 102, 152. What is the average of the
extracted scores that are extreme values (outliers)?

Answer 1

Given : The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

To find : average of the extracted scores that are the extreme values (outliers)

Solution:

The average marks of candidates in an aptitude test was 128.5

=> Mean = 128.5

Standard Deviation = 8.2

outlier will be out sides   then range    Mean  ± 3* SD

128.5 ± 8.2 × 3

= 128.5 ± 24.6

Range is   ( 103.9  ,  153.1)

102 is outside this range

Hence outlier would be 102

Average of 102   will be 102

Learn more:

Sora was given two data sets, one without an outlier and one with an ...

https://brainly.in/question/16801317

Which set of data contains one outlier? 15, 19, 26, 51, 18, 21 22, 33 ...

https://brainly.in/question/10416794