English, asked by anabhardwaj097, 2 months ago

The average marks of 10 students is 41. If the average marks of the top 6 and bottom 5 rankers are 45 and 36 respectively, how much did ​

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Answered by vipinkumar212003
1

Answer:

 \blue{let \: marks \: of \: 6th \: student = x} \\  \blue{Average \: marks \: of \: 10 \: students = 41} \\  \blue{ \frac{Total \: marks \: of \: 10 \: students}{10} = 41 } \\  \blue{  \boxed{Total \: marks \: of \: 10 \: students = 410  }  - (i)}\\ \blue{Average \: marks \: of \: top \: 6 \: students = 45} \\ \blue{ \frac{Total \: marks \: of \: top \: 5 \: students + x}{6} = 45 } \\\blue{ \boxed{ Total \: marks \: of \: top \: 5 \: students = 270 - x} - (ii) } \\ \blue{Average \: marks \: of \: bottom \: 5 \: students =36} \\ \blue{ \frac{Total \: marks \: of \: bottom \: 4\: students  +  x}{5} = 36 } \\\blue{ \boxed{ Total \: marks \: of \:bottom \: 4 \: students = 180  -  x} - (iii)} \\ \blue{\mathfrak{\underline{\large{put \: the \:value \: of \:  {eq}^{n}  \: (ii) \: and \: (iii)  \: in \: (i)}}}:} \\  \blue{270 - x + 180 - x = 410} \\  \blue{450 - 2x = 410} \\  \blue{2x = 40} \\  \blue{  \rightarrow{\boxed{ x= 20}}} \\ \blue{\mathfrak{\large{Marks \: of \: 6th \: student =  x= 20}}} \\ \blue{\mathfrak{\large{Total \: marks \: of \: top  \: 5 \: students = 270 - x = 250}}} \\ \blue{\mathfrak{\large{Total \: marks \: of \:bottom  \: 4\: students = 180- x = 160}}} \\  \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}

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