Math, asked by charanvarun2007, 1 month ago

The average marks of 10 students is 41. If the average marks of the top 6 and bottom 5 rankers are 45 and 36 respectively, how much did the 5th ranker score?

41

42

43

40

Answers

Answered by Anonymous
8

Answer:

5 th score 40 marks hope it helps you

Answered by hukam0685
0

Score of 5th ranker is 40.

Option (d) is correct.

Given:

  • The average marks of 10 students is 41.
  • If the average marks of the top 6 and bottom 5 rankers are 45 and 36 respectively.

To find:

  • Find the score of 5th ranker.
  • (a) 41
  • (b) 42
  • (c) 43
  • (d) 40

Solution:

Concept /Formula to be used:

  • \bf Mean=\frac{\Sigma \: x_i}{n} \\

  • 5th ranker score is counted twice.

Step 1:

Find the sum of marks of all 10 students.

Mean/ Average = 41

n= 10

Sum of marks of all 10 students:

= 41×10

= 410

Step 2:

Find the sum of marks of top 6 students.

Mean= 45

n= 6

Sum of marks of top 6 students:

= 45×6

=270

Step 3:

Find the sum of marks of bottom 5 students.

Mean= 36

n= 5

Sum of marks of bottom 5 students:

= 36×5

= 180

Step 4:

Add the results of step 2 and 3.

Sum of marks(5th ranker score is repeated twice) :

= 270+180

= 450

Step 5:

Subtract result of step 4-step 1.

Score of 5th ranker = 450-410

Score of 5th ranker = 40

Thus,

Score of 5th ranker is 40.

Option (d) is correct.

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