Question

The average marks secured by a group of 45 students was 41. Later on it was discovered that a score of 92 was misread as 29. Find the correct average marks secured by them.

Answer 1

Answer:

corrected average=42.4

Step-by-step explanation:

Formula used:

$Average=\frac{\Sigma{x}}{n}$

Given:

Average =41

$\frac{\Sigma{x}}{n}=41$

$\frac{\Sigma{x}}{45}=41$

$\implies\:\Sigma{x}=45*41$

$\implies\:\Sigma{x}=1845$

As per given data,

$corrected\:\Sigma{x}=1845-29+92$

$corrected\:\Sigma{x}=1908$

Now,

$corrected\:average=\frac{corrected\:\Sigma{x}}{n}$

$corrected\:average=\frac{1908}{45}$

$corrected\:average=42.4$