Question

The average mass of one gold atom in a sample of naturally occuring gold is 3.2707x10-22g. Use this to calculate the molar
mass of gold.​

Answer 1

The average mass of one gold atom in a sample of naturally occuring gold is 3.2707x10-22g. Use this to calculate the atomic mass of gold.

solution : 196.96 g

The average mass of gold atom in a sample of naturally occurring gold is 3.2707 × 10^-22 g.

we know, mass of an atom is equal to ratio of atomic mass to Avogadro's number.

or, atomic mass = Avogadro's number × mass of one atom.

or, atomic mass = 6.022 × 10²³ × mass of one atom.

so, atomic mass of gold = 6.022 × 10²³ × mass of a gold atom.

= 6.022 × 10²³ × 3.2707 × 10-²² g

= (6.022 × 3.2707) × 10¹

= 19.6961554 × 10 g

= 196.96 g

hence, atomic mass of gold = 196.96 g

Answer 2

Explanation:

The average mass of gold atom in a sample of naturally occurring gold is 3.2707 × 10^-22 g. we know, mass of an atom is equal to ratio of atomic mass to Avogadro's number. or, atomic mass = Avogadro's number × mass of one atom. or, atomic mass = 6.022 × 10²³ × mass of one atom

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