Question

The average molceular mass of a mixture of gas
containing nitrogen and carbon dioxide is 36. The
mixture contain 280 gm of nitrogen, therefore, the
amount of Co, present in the mixture is -
| (1) 440 g
(2) 449
(3) 0.1 mole
(4) 880 g
​

Answer 1

Solution :

Moles of N2 gas = 280/28 = 10 moles

Molecular mass of CO2 gas = 44 grams

Let us assume that the moles of carbon dioxide gas (CO2) = x

So, the average molecular mass of mixture.

=> 10 × 28 + x × 44 / 10 + x = 36

=> 280 + 44x / 10 + x = 36

=> 280 + 44x = 360 - 36x

=> 44x - 36x = 360 - 280

=> 8x = 80

=> x = 80/8 = 10

.°. x = 10

So, x = 10 moles

.°. The amount of CO2 gas = 10 × 44 = 440 grams

Answer 2

Answer:

440gtrfggytftttrerghgdhdgffndgwggjtfkddbedb