Math, asked by zknight841, 3 months ago

The average monthly income of 6 employees
is Rs. Rs. 310. After one of them receives an
increment, the average rises to Rs. 312.50.
The amount of increment is​

Answers

Answered by kavyapatel93
0

Answer:

Answer is Rs.19,200

Step-by-step explanation:

Rs.19,200.

Rs.19,200.Let the salary of the manager be x

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000Total Salaries = 153000+x

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000Total Salaries = 153000+xNew mean = 7650+550=8200

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000Total Salaries = 153000+xNew mean = 7650+550=8200Total Salaries = 21×8200 = 171150

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000Total Salaries = 153000+xNew mean = 7650+550=8200Total Salaries = 21×8200 = 171150Hence, 153000+x=172200

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000Total Salaries = 153000+xNew mean = 7650+550=8200Total Salaries = 21×8200 = 171150Hence, 153000+x=172200x=172200−153000

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000Total Salaries = 153000+xNew mean = 7650+550=8200Total Salaries = 21×8200 = 171150Hence, 153000+x=172200x=172200−153000x=19200

Rs.19,200.Let the salary of the manager be xSum of salaries of employees = 20×7650=153000Total Salaries = 153000+xNew mean = 7650+550=8200Total Salaries = 21×8200 = 171150Hence, 153000+x=172200x=172200−153000x=19200Hence, manager's salary is Rs 19,200

Answered by Shyam75goga
0

Answer:

Thad has blessed by n I don't have a data is off the

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