The average number of errors in a page of a book is 1.4 the probability page will contains four errors is
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Given : The average number of errors in a page of a book is 1.4
To Find : the probability page will contains four errors is
Solution:
Poisson distribution
P(x) = { λˣ e^(-λ) } / x!
λ = Mean = 1.4
probability of 4 errors in 1 page
= P(4)
= { 1.4⁴ e^(-1.4) } / 4!
= 0.0395
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