Question

The average number of phone 1 point
calls per minute in a call centre
is 4. Find the probability that
during a specific minute, the
number of calls is less than 2.
(Given : e^(-4) = 0.0183)
O a) 0.0732
O b) 0.1464
O c) 0.9085
O d) 0.0915​

Answer 1

Answer:

0.0915

Step-by-step explanation:

p = (e^(-r))(r)^x

---------------

x!

x=no of success in the question

r=mean of success

for no of calls =1

p1 = (e^(-4))(4)^1

---------------- = 4 * (0.0183)

1!

for no of calls =0

p0 = (e^(-4))(4)^0

----------------- = 1 * (0.0183)

0!

as per the question

required probability = p0 + p1

= [4*(0.0183)]+[1*(0.0183)]

=0.0915