Question

The average of 1, 3, 5, 7, 9, 11,
........ to 25 terms is

Answer 1

Answer:

I hope it will help u

Step-by-step explanation:

The number of terms is

N = (25 - 1) / 2  + 1 = 13

The sum of terms, which is the arithmetic progression with difference 2, is:

S = (1 + 25) × 13 ÷ 2 = 13 × 13

The average is:

A = S / N = 13 × 13 / 13 = 13

So, to calculate the average of arithmetic progression was needed to calculate the number of terms N, the average arithmetic progression is the average of first and last term:

A = (1 + 25) / 2 = 13