The average of 10 numbers is 40.2 . Later it is found that two numbers have been wrongly copied . The first is 18 greater than the actual number and the second number added is 13 instead of 31 . Find the correct average .
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the average number remain same
rohitchak21pam42i:
no they dont
first no. is 18 greater than actual no. and the second ni. is 18 less . thus the difference became zero and average remain same
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n/10 =40.2
n=402
sum of all no. =402
31-13=18
=402+18+18/10
=438/10
average =43.8
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