the average of 10 observations was 30 if two observations 45and55 are removed what is the average of remaining observations
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Answered by
0
Answer:
n=50
x
ˉ
=38
∑x=n×
x
ˉ
=50×38=1900
if 45 and 55 discarded
∑x
new
=1900−(45+55)=1800
Now n=48
x
ˉ
=
n
∑x
new
=
48
1800
=37.5
Answered by
0
Answer:
your answer is =37.5
Explanation:
i hope it will help you
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