Question

The average of 10 observations was 30. If two observations 45 and 55 are removed. What is the average of remaining observations







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Answer 1

Answer:

x/10=30

x=300

(x-(55+45)) /8 = (300-100) /8 =200/8=25

answer is 25

Answer 2

Step-by-step explanation:

Given :-

The average of 10 observations was 30. If two observations 45 and 55 are removed.

To find :-

What is the average of remaining observations ?

Solution :-

Given that

The average of 10 observations = 30

We know that

Average = Sum of all observations/Number of all observations

=> 30 = Sum of all observations / 10

=> Sum of all observations = 30×10

=> Sum of all observations = 300

Removed observations = 45 and 55

The sum of remaining observations

=> 300 - (45+55)

=> 300-100

=> 200

Remaining observations = 10-2 = 8

The average of remaining observations

= Sum of remaining observations/ Number of remaining observations

=> Average = 200/8

=> Average = 25

Answer:-

The average of remaining observations is 25

Used formulae :-

→ Average = Sum of all observations/Number of all observations