Question

the average of 11 numbers is 20.if the average of first six numbers is 19 and that of the last six numbers is 22,the the middile numbers is what

Answer 1

average=20
mean=sum/total
20=sum/11
sum=20×11=220
FIRST SIX
average=19
mean=sum/total
19=sum/6
sum=19×6=114
LAST SIX
average=22
mean=sum/total
22=sum/6
sum=22×6=132
therefore the middle number is 132-114=18
because it comes both in the first six and the last six numbers

Answer 2

Answer:

The middle term is 18

Step-by-step explanation:

They have given that the average of 11 numbers is 20

$Average = \frac{sum}{n}$

Here, n is the number of observations.

$20=\frac{sum}{11}$

Sum of 11 numbers = 220

They have given that the average of the first six numbers is 19

$19=\frac{sum}{6}$

Sum of the first six numbers= 114

They have given that the average of the last six numbers is 22

$22=\frac{sum}{6}$

Sum of the last six numbers = 132

The middle term = sum of last six numbers - sum of first six numbers

                            = 132 - 114

                            = 18

Therefore the middle term is 18