The average of 13 consecutive numbers is 324. If there is another series which starts with the same number as the previous series, then what is the average of the first 20 consecutive numbers of...
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2
let the no be a-6d,a-5d,a-4d,a-3d,a-2d,a-d,a,a+d,a+2d,a+3d,a+4d,a+5d,a+6d
so
13a/13=324
a=324
now for 20
20a/20=a=324
so
13a/13=324
a=324
now for 20
20a/20=a=324
Answered by
2
(x+x+1+x+2...+x+11+x+12)/13=324
13x+78=324*13
13x=4212-78
13x=24134
x=318
average of first 20 consecutive no.=(x+x+1+..+x+19)/20
(20x+190)/20=(20*318+190)/20
10(636+19)/20=655/2
327.5
13x+78=324*13
13x=4212-78
13x=24134
x=318
average of first 20 consecutive no.=(x+x+1+..+x+19)/20
(20x+190)/20=(20*318+190)/20
10(636+19)/20=655/2
327.5
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