Question

The average of 13scores in 8.If one of the score 20 is deleted from them,then the average of the remaining scores is?

Answer 1

Avg.=8 n=13 Avg.= Sum/n 8=Sum/13 108=Sum When 20 is deleted Sum=108-20=88 Now, Sum=88 n=13-1=12(as one term is deleted) Avg.=88÷12=7.34(approx)

Answer 2

Answer: Average of remaining scores would be 7.

Step-by-step explanation:

Since we have given that

Number of scores = 13

Average = 8

$Average=\dfrac{Sum}{13}$

So, sum of 13 scores would be

$13\times 8\\\\=104$

If score 20 is deleted from them,

Sum would be

$104-20=84$

Number of remaining scores = 12

So, Average of remaining scores would be

$\dfrac{84}{12}=7$

Hence, average of remaining scores would be 7.