Question

The average of 19 consecutive even integers is 50. The highest of these integers is

A) 88 B) 68 C) 126 D) 100

Answer 1

Answer:

the answer is Option B that is 68..

Step-by-step explanation:

let the lowest even integer be x

the sum of 19 even integer =50×19=950

1. 1st integer =x
2. 2nd integer =x+2
3. 3rd integer =x+4
4. 4th integer=x+6
5. 5th integer =x+8
6. 6th integer =x+10
7. 7th integer =x+12
8. 8th integer =x +14
9. 9th integer =x+16
10. 10th integer =x+18
11. 11th integer =x+20
12. 12th integer =x+22
13. 13th integer =x+24
14. 14th integer =x +26
15. 15th integer =x +28
16. 16th integer =x+30
17. 17th integer =x +32
18. 18th integer =x +34
19. 19th integer =x +36

the highest integer is x+36

sum of the 19 even integer =19x+342

according to question; 19x+342=19×50

so,x=32

the highest integer =x+36=32+36=68

so the answer is 68..

Hope it helps you mate!!!!