the average of 1st "n" even numbers?
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The idea is the sum of first n even number is n(n+1), for find the Average of first n even numbers divide by n, hence formula is n(n + 1) / n = ( n + 1).
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3
Answer:
The sum of first n even number = n(n+1) For find the Average of first n even numbers divide by n,
Hence formula =n(n + 1) / n
= ( n + 1)
The average of 1st "n" even numbers =(n+1)
Hope it helps! ! !
saikirankamarthi995:
hi
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