Question

The average of 29 consecutive even integers is 60 the highest of these integers is

Answer 1

Answer:

Step-by-step explanation:

first even no be n

next one will be n+2 and then n+4 and so on.. till n+56

average of numbers = n+n+2+n+4+......+ n+56/ 29

(29n + 2+4+....+56) / 29 =60

2+4+..+56 = 28/2[2*2 + (28-1)2]           (sum of AP with d=2)

                =14*58=812

29n+ 812=29*60=1740

29n=928

n=32

highest value =n+56=32+56=88

Answer 2

Answer:

32

Step-by-step explanation:

find the sum of all the 29 consecutive even integers below 60( including 60)

the sum will be 928

then,

928/29=32

hope it helps you

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