the average of 3 6 9 of 12
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Method 1 (logic):
3,6,9,12,15,18,…. Is equivalent to 3(1,2,3,4,5,6…)
Tn (nth term) is 3n
Method 2 (sequences and series):
AP with common difference of 3 and first term 3, t1=3, tn= t1+(n-1)d= 3+(n-1)3= 3n
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