Question

The average of 3, 8, 9 and x is 6 and the average of 17, 2, 5, x and y is 8. What is the value
of y?​

Answer 1

Answer:

$\qquad\sf {:}\longrightarrow 3+8+9+x/4=6$

$\qquad\sf {:}\longrightarrow 20+x/4=6$

$\qquad\sf {:}\longrightarrow 20+x=24$

$\qquad\sf {:}\longrightarrow x=24-20=4$

$\qquad\sf {:}\longrightarrow 17+2+5+x+y/5=8$

$\qquad\sf {:}\longrightarrow 24+x+y/5=8$

$\qquad\sf {:}\longrightarrow 24+4+y=40$

$\qquad\sf {:}\longrightarrow 28+y=40$

$\qquad\sf {:}\longrightarrow y=40-28=12$

Answer 2

Answer: The correct answer is 12. The value of y is 12 when the average of 3, 8, 9 and x is 6 and the average of 17, 2, 5, x and y is 8.

Step-by-step explanation:
It is given in the question that

Average of 3, 8, 9 and x = 6
Average means sum of total number of observations is divided by number of observations.

From the definition of average we can write that

⇒ $\frac{3+8+9+x}{4} = 6$
⇒$\frac{3+8+9+x}{4} = 6$
⇒ $\frac{20+x}{4} = 6$
⇒$20+x = 24$
⇒$x= 24- 20$
∴$x = 4$

Morever , it is given in the question that
Average of 17, 2, 5, x and y = 8

⇒$\frac{17+2+5+x+y}{5} = 8$
⇒ $\frac{24+x+y}{5} = 8$

Putting the value of x from above, we get

⇒$\frac{24+4+y}{5} = 8$
⇒ $\frac{28+y}{5} = 8$
⇒$28+y = 40$
∴$y = 12$

Hence, the value of y is 12 when the average of 3, 8, 9 and x is 6 and the average of 17, 2, 5, x and y is 8.


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