The average of 3consecutive odd numbers A, B and C is 45.what is the sum of A and C?
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Let the consecutive odd numbers be n+1,n+3,n+5
Acc. To the problem,
n+1+n+3+n+5=45
3n+9=45
3n=45-9
3n=36
n=36/3
n=12
A=n+1=12+1=>13
C=n+5=12+5=>17
Sum of A and C=13+17=30
Acc. To the problem,
n+1+n+3+n+5=45
3n+9=45
3n=45-9
3n=36
n=36/3
n=12
A=n+1=12+1=>13
C=n+5=12+5=>17
Sum of A and C=13+17=30
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