Question

The average of 4 consecutive even numbers A,B,C,D is 99 is

Answer 1

Answer:

question pura bej do please

Answer 2

a=n

b=n+2

c=n+4

d=n+6

their sums =99

n+(n+2)+(n+4)+(n+6)/4=99

4n+12= 396

4n=396-12

4n=384

n=384/4

n=96

so,a=96

b=96+2=98

c=96+4=100

d=96+6=102