Question

The average of 4 positive integers is 72.5. The highest integer is 117 and the lowest integer is 15. The difference between the remaining two integers is 12. Which is higher of these remaining two integers?

Answer 1

Answer:

The highest of the remaining two is 85

Step-by-step explanation:

Let the remaining two integers be x and y

By data average=72.5

117+x+y+15=72.5×4

132+x+y= 290

x+y= 158

The difference between the two x-y=12

Adding equation 1 and 2 we get x=85