Question

The average of 46 natural no is?

Answer 1

avg of first n natural numbers is n+1/2

= 47/2 = 23.5

Answer 2

Answer- The average of 46 natural numbers is 23.5

Given: First 46 natural numbers 1, 2, 3, ..., 46

To find: The average of 46 natural numbers

Solution:

We know,

Average/mean of n natural numbers= $\frac{sum of n natural numbers}{n}$

⇒ Average of 46 natural numbers= $\frac{1 + 2 + 3 +....+ 46}{46}$ [i]

Now,

Sum of first 46 natural numbers = $\frac{46(46 + 1)}{2}$ = 1081 [ii]

[∵ sum of n consecutive natural numbers = $\frac{n(n + 1)}{2}$]

⇒ Average = 1081/46 [from i and ii]

⇒ Average = 23.5 Answer

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