Question

The average of 5 conjugative even number a,b,c,d,e is 52 what is the product of b,e

Answer 1

Answer:

The Product of b & e => 2800

Step-by-step explanation:

Hey Mate,

5 Conjunctive Even Number are,

X(a) , X + 2(b) , X + 4(c), X + 6(d) , X + 8(e) .

Average = 52.

{ X + (X + 2) + (X + 4) + (X + 6) + (X + 8) } / 5 = 52

(5X + 20)/5 = 52

5X + 20 = 260

5X = 240

X = 48.

The Product of b & e => (X+2) × (X+8)

=>  50 × 56

=> 2800

Answer 2

a/c to question, The average of 5 conjugative even number {a, b, c, d, e} is 52.

if a is first even number,
b = a + 2 ,
c = a + 2 + 2 = 4,
d = a + 2 + 2 + 2 = a + 6
e = a + 2 + 2 + 2 + 2 = a + 8

so, average of a , b, c , d and e = (a + b + c + d + e)/5

or, 52 = {a + (a + 2) + (a + 4) + (a + 6) + (a + 8)}/5

or, 260 = 5a + (2 + 4 + 6 + 8)

or, 260 = 5a + 20

or, 5a = 240

hence, a = 48 , b = a + 2 = 50 , c = a + 4 = 52

d = a + 6 = 54 and e = a + 8 = 56

now, product of b and e = 50 × 56 = 2800