Question

The average of 5 consecutive
numbers is 18. The highest of these
numbers will be
(a) 24
(b) 18
(c) 20
(d) 22​

Answer 1

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☆ ANSWER:-

▪︎ Given:-

• Average of 5 consecutive integers = 18.

▪︎ To Find:-

• The highest of these number.

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▪︎ Formula Used:-

$\sf\leadsto Average =\frac{Sum\:of\:all\:Observations}{Total \:no. \:of \:observations}$

▪︎ So,

• Let the 5 consecutive integers be (x), (x+1), (x+2), (x+3) and (x+4).

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▪︎ Now, ATQ:-

$\\ \\\tt\small\mapsto \frac{(x) + (x + 1) + (x + 2) + (x + 3) + (x + 4)}{5} = 18. \\ \\ \tt\mapsto \frac{x + x + 1 + x + 2 + x + 3 + x + 4}{5} = 18. \\ \\ \tt\mapsto\small \frac{5x + 10}{5} = 18. \\ \\ \tt\mapsto \frac{\cancel5(x + 2)}{\cancel5} = 18. \\ \\ \tt\mapsto \: x + 2 = 18. \\ \\ \tt\mapsto \: x = 18 - 2. \\ \\ \tt\mapsto \: x = 16.$

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▪︎ Therefore the integers are:-

• x = 16.

• x+1 = 16+1 = 17.

• x+2 = 16+2 = 18.

• x+3 = 16+3 = 19.

• x+4 = 16+4 = 20.

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▪︎ Clearly we can see that highest of these numbers are 20.

$\therefore$ Your Answer is Option C:- 20.

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