Question

the average of 5 number is 180.if one number is removed thenthe average is 155.find removed number.​

Answer 1

Answer:

Step-by-step explanation:

Let the five is a ,b ,c ,d ,e so (a+b+c+d+e)/5=180 a+b+c+d+e=900 .......(1). (a+b+c+d)/4=155. a+b+c+d=620. ...….(2).

Put the value of (2)eqn

in eqn (1) a+b+c+d+e=900 620+e=900 so e=900-620=280 therefore fifth number is 280

Answer 2

The removed number is 280

Step-by-step explanation:

$Average = \frac{\text{Sum of all observations}}{\text{No. of observations}}$

We are given that the average of 5 number is 180

So, $180 =\frac{\text{Sum of 5 numbers }}{5}\\180 \times 5= \text{Sum of 5 numbers }\\900=\text{Sum of 5 numbers }$

One number is removed then the average is 155

Let removed number be x

So, total observations = 4

New sum = 900-x

So, $155= \frac{900-x}{4}\\155 \times 4 = 900-x\\620=900-x\\x=900-620\\x=280$

Hence The removed number is 280

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