Question

the average of 5 terms is 50 . if the first 4 terms are 45,42,119 and 84 what will be the last terms​

Answer 1

$\huge\bigstar\sf\red{Answer:}$

$\sf{Average=\dfrac{Sum \ of \ observations}{Number \ of \ observation}}$

$\sf{50=\dfrac{45+42+119+84+(Fifth \ term)}{5}}$

$\sf{\therefore{45+42+119+84+(Fifth \ term)=5\times50}}$

$\sf{\therefore{290+(Fifth \ term)=250}}$

$\sf{\therefore{Fifth \ term=250-290}}$

$\sf{\therefore{Fifth \ term=-40}}$

$\sf{The \ fifth \ term \ is \ -40.}$

Answer 2

Answer:

-40

Step-by-step explanation:

let the fifth term be x

average of the terms is 5.

45+42+119+84+x/5 = 50

290+x/5 = 50

290+x = 50×5

290+x = 250

x = 250-290

x = -40