The average of 6 consecutive even numbers is 207. what will be the sum of the smallest and largest number?
Answers
Answered by
5
x+(x+2)+(x+4)+(x+6)+(x+8)+(x+10))/6=207
6x+30=1242
6x=1212
x=1212/6=202
x+x+10=2x+10=2×202+10
=414
6x+30=1242
6x=1212
x=1212/6=202
x+x+10=2x+10=2×202+10
=414
Answered by
0
Given - Average
Find - Sum of smallest and largest number
Solution - Let the 6 consecutive even numbers be x, (x+2), (x+4), (x+6), (x+8) and (x+10).
Average = sum of all numbers/total numbers
Sum of all numbers = x + x+2 + x+4 + x+6 + x+8 + x+10
Performing addition
Sum of all numbers = 6x + 30
Keep the values in formula -
207 = (6x + 30)/6
6x + 30 = 207*6
Performing multiplication
6x + 30 = 1242
6x = 1242 - 30
Performing substraction
6x = 1212
x = 1212/6
Performing division
x = 202
Largest number = x + 10
Largest number = 202 + 10
Largest number = 212
Smallest number = x
Smallest number = 202
Sum = 202 + 212
Sum = 414
Hence, sum of the smallest and largest number as per the question is 414.
Similar questions