Question

the average of 7 different numbers is 80 four of these numbers are greater than 80 and three are less than 80 a) find the sum of the number b)the sum of three numbers less than 80 is 230 what is the sum of 4 numbers greater than 80​

Answer 1

Answer:

Say,

A+B+C+D = 4*8 = 32 --- Eq (1)

Then,

D+E+F+G = 4*20 = 80 --- Eq (2)

Hence, Eq2-Eq1

= D + (E+F+G) - (A+B+C) - D

= (E+F+G) - (A+B+C) , i.e. difference between the sums of the three greatest number and the three smallest numbers

= 80 - 32

= 48

Step-by-step explanation: