Question

the average of 8 numbers is 14 of these if the average of 6 number is 16 what is the average of remaining two numbers
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Answer 1

Answer:

answer is 8

Step-by-step explanation:

Average of 8 numbers = 14

Sum of 8 numbers = 14×8=112

Similarly, average of 6 numbers = 16

Sum of 6 numbers = 16×6=96

Therefore, Sum of remaining two numbers = Sum of 8 numbers - Sum of 6 numbers

= 112 - 96 = 16

Average = Sum of two number2=162=8

Answer 2

Answer:

The average of remaining two numbers are 7.95

Step-by-step explanation:

let ,

The 8 numbers are $x , 2x , 3x, 4x, 5x,6x, 7x,8x$

Average means sum of all number divided by the total numbers.

The average of 8 numbers is 14

$\frac{x+2x+3x+4x+5x+6x+7x+8x}{8} = 14$

$x+2x+3x+4x+5x+6x+7x+8x = 14$ ×$8$

$x+2x+3x+4x+5x+6x+7x+8x = 112$      . . . . . . . (1)

The average of 6 number is 16

$\frac{x+2x+3x+4x+5x+6x}{6}=16$

$x+2x+3x+4x+5x+6x = 16$ × $6$

$x+2x+3x+4x+5x+6x = 96$

So, sum of these x+2x+3x+4x+5x+6x number is 96

put these value in equation (1)

$96+7x+8x = 112\\15x = 112-96\\15x = 16\\x = \frac{16}{15} \\x = 1.06$

The last two number is $7x$ and $8x$

$7x = 7$ ×$1.06 = 7.42$

$8x = 8$ × $1.06 = 8.48$

We have to now find average of it

$\frac{7.42 + 8.48}{2}$

$= \frac{15.9}{2} \\= 7.95$

The average of remaining two numbers are 7.95