Question

The average of 9 consecutive numbers is 40 .Find the largest number .

Answer 1

Hope you like my answer
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=> Let the smallest number be x

=> So the numbers are

x, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8

=> Sum of the numbers = 9x + 36

=> Average = Sum/9 = 9(x+4)/9 = x+4

By problem
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=> Average = 40

=> x+ 4 = 40

=> x = 40-4 = 36

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So the largest number is

=> x +8 = 36 +8 = 44 ____(answer)

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Answer 2

$\textbf{ANSWER}$

Let the smallest no. be x

sum of the no. = 9x + 36

Average
$= \frac{sum}{9} \: = \: \frac{9(x + 4)}{9} \: = \: x + 4$

Hence,

» Average = 40

» x + 4 = 40

» x = 40 - 4 = 36

Therefore, the largest number is..

» x + 8 = 36

» 36 + 8 = 44



$\textbf{ANS}$ : 44 is the largest number.