Question

The average of a and b is an+1 + bn+1/an+bn find the value of n

Answer 1

Answer:

The value of n is 4/ (a+b)* (a+b-2)

Step-by-step explanation:

The average of two number = a+b/2

According to the question,

a+b/2 = an+1+bn+1/ an+bn

a+b/2= an+bn +2/ n(a+b)

a+b/2 = n(a+b) +2/ n (a+b)

(a+b)/2* n (a+b) = n (a+b) +2

n (a+b)²/2- n (a+b)  =  2

n (a+b)* ( a+b-2) = 4

n= 4/ (a+b)* (a+b-2)

The value of n is 4/ (a+b)* (a+b-2)