Math, asked by endalebdumath6120, 10 months ago

The average of a n ok non-zero number and its square is 10 times the number.then the number is how much

Answers

Answered by hashtagultralegend
0

Answer:

n = 10

Step-by-step explanation:

n^2 = 10n

n^2 - 10n = 0

n ( n - 10 ) = 0

n = 0 or 10.

Since n is a non - zero number, n = 10

Answered by Anonymous
0

The required number is 19.

Given: Average of n and n^2 = 10*n

Therefore, solving for n:

( n + n^2)/2 = 10*n

n + n^2 = 20*n

n^2 - 19*n = 0

n ( n -19 ) = 0

Hence, n = 0 and n = 19

We only need non-zero number, therefore n =19

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