Math, asked by singhabhi5942, 9 months ago

The average of eight numbers is 4.6. The average of three of them is 4.2, while th average of other three is 4.4 what is th average of the remaining two numbers?

Answers

Answered by padmanava75
31

Answer:

Average of 8 = 4.6

Then sum = 8×4.6 = 36.8

Average of 3 = 4.2

Sum = 3×4.2 = 12.6

Average of another 3 = 4.4

Sum = 3× 4.4 = 13.2

Then average of 2 = [ 36.8 - ( 12.6 + 13.2 ) ] ÷ 2 = 5.5

Answered by hsksai999
8

Answer:

5.5

Step-by-step explanation:

average of 8 numbers = 4.8

then sum = 4.6×8 =

average of 3 of them = 4.2

then sum = 4.2×3 = 12.6

average of other 3 of them = 4.4

then sum = 4.4×3 = 13.2

average of remaining 2 numbers = x

x = [36.8-(12.6+13.2)]/2

x = [36.8-25.8]/2

x = 11.0/2

x = 11/2 = 5.5

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