Question

The average of first 50 natural number are?​

Answer 1

numbers is (1+2+3+…..+n) = n(n+1)/2

Herw n=50

Sum of 50 natural number = (1+2+3+…..+50) = [50(50+1)/2] = [50 * 51/2 ] =1275

Therfore, the average of first 50 natural numbers = [n(n+1)/2]/n = 1275/50 = 25.5

Answer 2

Answer:

kya majak...........